Question

What is the equation of the following graph in vertex form?

parabolic function going down from the left through the point zero comma twelve and through the point two comma zero and turning at the point four comma negative four and going up through the point six comma zero and continuing towards infinity

Answer 1

@wolf1728 @sleepyhead314

Answer 2

I will assume that the "turning point" would be the vertex

Answer 3

vertex form is:
\(y=a(x-h)^2+k\)
where \((h,k)\) is the vertex point

and I forgot how to find a >,<

Answer 4

heres the pic of the graph

Answer 5

sorry can't get the pic

Answer 6

here are the answer choices though:
y = (x − 4)2 − 4
y = (x + 4)2 − 4
y = (x + 2)2 + 6
y = (x + 2)2 + 12

Answer 7

well you know the vertex is (4, -4)

so the equation is

\[y = a(x -4)^2 - 4\]

to find the value of a, substitute any point on the curve, other than the vertex, into the equation to find a

Answer 8

so it would be B?

Answer 9

help please guys @sleepyhead314 @wolf1728

Answer 10

take a look at what campbell_st wrote :)

Answer 11

i need the answer i still have to study for a test and i just need help please @sleepyhead314

Answer 12

campbell has showed clearly what your answer should be :)

Answer 13

campbell said the equation is
y=a(x−4)^2−4

Answer 14

thank you guys, sorry a bit tired here