Where does the graph of y = sin x from x = 0 to x = 2π start?

Question

butterflydreamer · Answer

A simple way to approach this question is to simply plug in "x = 0" into "y = sin x"
so work out what y = sin 0 equals to  and this will tell you where the graph begins :)

anonymous · Answer

the answer is at its maximum?

butterflydreamer · Answer

hmm.. what do you mean?

butterflydreamer · Answer

Do you know what your standard y = sinx graph looks like? :)

anonymous · Answer

im not sure what that is I just got into trig today

butterflydreamer · Answer

hmm.. okay. Well here's what your standard y = sinx graph will look like : http://www.wolframalpha.com/input/?i=y+%3D+sinx+ And here's what your y= sinx graph will look like from x = 0 to x = 2pi http://www.wolframalpha.com/input/?i=y+%3D+sinx+from+x+%3D+0+to+x+%3D+2pi

butterflydreamer · Answer

Since they've told us the boundaries (so the start and end of your graph) are x = 0 and x = 2pi.
I guess you could say that the graph starts at (0,0) right?
Since x = 0, and if we sub that into our equation : y = sinx... we get:
 y = sin 0 = 0

anonymous · Answer

thank you for the help much appreciated!

butterflydreamer · Answer

You're welcome ^_^!