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OpenStudy (meehan98):
Identifying Conic Sections help, please!
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OpenStudy (meehan98):
OpenStudy (anonymous):
Conic sections are the curves which can be derived from taking slices of a "double-napped" cone.
OpenStudy (meehan98):
I understand all of it besides the last part, and I have -9(x-7)^2 + 16 (y-5)^2=144
OpenStudy (meehan98):
I know that I multiply (1/144) by each side but the (-9) is throwing me off.
OpenStudy (madhu.mukherjee.946):
its an hyperbola
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OpenStudy (meehan98):
But How do you get the final equation so you know it's a hyperbola?
OpenStudy (madhu.mukherjee.946):
-9 (x-14) x+16 (y-10) y-185 = 0
OpenStudy (madhu.mukherjee.946):
-9 (x-7)^2+16 (y-5)^2-144 = 0
OpenStudy (meehan98):
So, the final equation we want looks like this: (x-h)^2/a^2-(y-k)^2/b^2=1
From your equation above, is the next step to divide 144?
OpenStudy (madhu.mukherjee.946):
yeah
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OpenStudy (meehan98):
OKay, this is where I get confused because wouldn't it be: -9/144(x-7)^2+16/144(y-5)^2=1
OpenStudy (madhu.mukherjee.946):
yes
OpenStudy (madhu.mukherjee.946):
did i help you?
OpenStudy (meehan98):
Sorry my computer crashed. Ok so I'm getting an ellipse. (X+7)^2/16 + (y-5)^2/9=1
OpenStudy (madhu.mukherjee.946):
nope its an hyperbola
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OpenStudy (meehan98):
When you divide 144 to -9(x-7)^2 would your result be (x+7)^2/16 because the -1 makes x-7^2 a positive (x+7)^2
OpenStudy (meehan98):
Never mind! I got it!! Thanks for your help! The equation would be: (y-50^2/9-(x-7)^2/16
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