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Mathematics 7 Online
oregonduck (oregonduck):

help with Pythagoras' Theorem

oregonduck (oregonduck):

the hypotenuse of the right triangle is 13 and the base is 5 what is the height show your work

Nnesha (nnesha):

\[\huge \rm a^2+b^2=c^2\] Pythagorean theorem c is the longest side( hypotenuse ) so plugin c and b value solve for a

oregonduck (oregonduck):

\[5^{2}+b ^{2}=13^{2}\]

Nnesha (nnesha):

looks good solve for b

oregonduck (oregonduck):

how?

Nnesha (nnesha):

btw base is b but that's not gonna change the answer

Nnesha (nnesha):

how would you cancel out 5^2 from left side ? would you add,subtract,multiply or divide by 5^2?

oregonduck (oregonduck):

mulitiply so...\[25+b ^{2}=169\]

Nnesha (nnesha):

that's right 25+b^2=169 now move 25 to the right side so how would you cancel out 25 from left side ?

oregonduck (oregonduck):

idk actullay

Nnesha (nnesha):

it's 25 `+`b^2 25 is positive at left side to cancel it out so should subtract 25 both sides

oregonduck (oregonduck):

i am confused

Nnesha (nnesha):

\[\huge\rm 25 +b^2=169\] we have to solve for b so subtract 25 both sides

oregonduck (oregonduck):

25=144

Nnesha (nnesha):

|dw:1442344735597:dw| both sides what would you get when you subtract 25 at left side ?

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