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oregonduck (oregonduck):
help with Pythagoras' Theorem
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oregonduck (oregonduck):
the hypotenuse of the right triangle is 13 and the base is 5 what is the height show your work
Nnesha (nnesha):
\[\huge \rm a^2+b^2=c^2\] Pythagorean theorem
c is the longest side( hypotenuse )
so plugin c and b value solve for a
oregonduck (oregonduck):
\[5^{2}+b ^{2}=13^{2}\]
Nnesha (nnesha):
looks good
solve for b
oregonduck (oregonduck):
how?
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Nnesha (nnesha):
btw base is b
but that's not gonna change the answer
Nnesha (nnesha):
how would you cancel out 5^2 from left side ?
would you add,subtract,multiply or divide by 5^2?
oregonduck (oregonduck):
mulitiply so...\[25+b ^{2}=169\]
Nnesha (nnesha):
that's right
25+b^2=169
now move 25 to the right side
so how would you cancel out 25 from left side ?
oregonduck (oregonduck):
idk actullay
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Nnesha (nnesha):
it's 25 `+`b^2
25 is positive at left side to cancel it out so should subtract 25 both sides
oregonduck (oregonduck):
i am confused
Nnesha (nnesha):
\[\huge\rm 25 +b^2=169\]
we have to solve for b
so subtract 25 both sides
oregonduck (oregonduck):
25=144
Nnesha (nnesha):
|dw:1442344735597:dw|
both sides
what would you get when you subtract 25 at left side ?
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