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Which of the following has the correct change in enthalpy and reaction description for the following reaction? NH3(g) + HCl(g) NH4Cl(s) Given: NH3: ∆H= -46.2 kJ HCl: ∆H= -92.3 kJ NH4Cl: ∆H= -314.43 kJ
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answer choices.. ∆H = -176 kJ and the reaction is exothermic. ∆H = -101 kJ and the reaction is endothermic. ∆H = -453 kJ and the reaction is endothermic. ÄH = -453 kJ and the reaction is exothermic. ∆H = -453 kJ and the reaction is isothermic.
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