Is it possible to have a piecewise function with only part of a circle?.. I know the equation isn't a function so I'm not sure if it's an actual thing...

Question

anonymous · Answer

I believe it's possible if you specify the domain.

anonymous · Answer

The only issue is the co-variant nature of that circle.

bloomlocke367 · Answer

I tried and it didn't do it :O that's why I was wondering.. I have a project where I have to make a picture using piecewise functions and I only need part of a circle but I can't figure out how to do it.

bloomlocke367 · Answer

@Nnesha

bloomlocke367 · Answer

@Shalante

anonymous · Answer

I am too trying to figure out how piecewise function works for my brother

anonymous · Answer

It appears pretty intuitive until you figure out each specified domain must also account for different equations.

bloomlocke367 · Answer

okay.. hmm

bloomlocke367 · Answer

@King.Void.

king.void. · Answer

Not good at math

bloomlocke367 · Answer

dang ok

beginnersmind · Answer

Think about the function 

$$f(x)= \sqrt{1-x^2}$$
compare it with the equation of a circle of radius 1 centered on the origin:
$$x^2+y^2 = 1$$

bloomlocke367 · Answer

@Shalante

jdoe0001 · Answer

you can have a function alone, and be only a semi-circle
a circle is compounded  of two semicircles really
each semi-circle occurs when you use the square root
the square root has a + and a - part, thus $\large \pm \sqrt{\quad}$

bloomlocke367 · Answer

that only shows half of the circle..

bloomlocke367 · Answer

yea okay XD I was about to say..

bloomlocke367 · Answer

but I'm working on a piecewise project and I have to create a picture on a graph using piecewise functions and that's why I was wondering XD