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How do I graph x^2=4y^2? Would someone mind making an x and y chart and showing me?
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first graph \(y_1=\sqrt{\dfrac{x^2}{4}}\) and then on the same graph, graph \[y_2=-\sqrt{\dfrac{x^2}{4}}\]
Because what you put is not a function, so we break it up into functions :)
x^2-4y^2=0 (x-2y)(x+2y)=0 so you should draw x-2y=0 and x+2y=0 .
Oh...how do you tell when to break up equations into two functions?
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both look good to me.. amirreza's even better...
sorry I read something completely different on my phone ....
thats zero product property @one2345 if you have an equation like : \(a*b = 0\), then it must be the case that either \(a = 0\) or \(b=0\) (or both of them equal to \(0\))
Oh I see, thank you so much.
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