Question

A train leaves the station at 9:00 pm traveling at 36 miles per hour. A second train leaves the station at 10:00pm traveling at 42 miles per hour. At what time will both trains have traveled the same distance?

A.) 4:00 am
B.) 5:00 am
C:) 6:00 am
D:) 7:00

Answer 1

I could figure it up and give you the answer, but I do it the difficult way.. Idk how to explain

Answer 2

I really need the answer I've been stuck for awhile. :/ please help!

Answer 3

Basically im just making a chart. and as you add an hour, add 36 or 42 cause thats how many miles they go per hour

Answer 4

Okay thanks :/ I tried that but I think I messed up

Answer 5

okok i got it

Answer 6

Its A

Answer 7

can i get a medal please, just hit Best Response

Answer 8

Just in case you are interested in a method to solve this:
Distance = Rate (mph) times time (hours) or D=RT This is the relationship you use.
For this problem, the distance traveled by first train will equal the distance traveled by second train.

Answer 9

D (distance) of first train = speed of first train times the time that the train traveled
D of 2nd train = speed of 2nd train times the time traveled by 2nd train.
The unknown here is the times. We now resort to algebra.

Answer 10

picking up from where @radar left off

Answer 11

36t = 42(t - 1)
36t = 42t - 42
-6t = -42
t = 7 hours

the trains have traveled the same distance 7 hours after the first train leaves the station. That's 4:00 am

Answer 12

Let X = the amount of time traveled by first train. Since 2nd train left an hour later .....then.....
X-1 = the amount of time traveled by 2nd train.
Since the distance traveled at the point where they were at the same place is the same.
36X = 42(X-1) Now all that is required is to solve for x. Add the value obtained for x to the time that first train left and you will have the time where both trains traveled the same distance.

PS For some reason there was a connection failure.

Answer 13

Let X = the amount of time traveled by first train. Since 2nd train left an hour later .....then.....
X-1 = the amount of time traveled by 2nd train.
Since the distance traveled at the point where they were at the same place is the same.
36X = 42(X-1) Now all that is required is to solve for x. Add the value obtained for x to the time that first train left and you will have the time where both trains traveled the same distance.

PS For some reason there was a connection failure.

Answer 14

However, I see that @peachpi has provided an excellent solution.