Question

need help

Answer 1

https://static.k12.com/bank_packages/files/media/mathml_63589419199f782841d0e7024dda1eb15980b1ff_1.gif

Answer 2

i need the power for like tro the 2nd power

Answer 3

\(\large\color{black}{ \displaystyle \frac{\left(12^{-5}\right)^2 }{12^{-4}} }\)

The first rule you need:
\(\large\color{black}{ \displaystyle \left(12^{A}\right)^B =12^{A~\times~B} }\)

Answer 4

what do you get on top of the fraction, after you apply this?

Answer 5

SO WHAT would it be

Answer 6

\(\large\color{black}{ \displaystyle \frac{\left(12^{-5}\right)^2 }{12^{-4}} }\)

\(\large\color{black}{ \displaystyle \frac{12^{(-5)\times 2} }{12^{-4}} }\)

\(\large\color{black}{ \displaystyle \frac{12^{-10} }{12^{-4}} }\)

\(\large\color{black}{ \displaystyle \left(\frac{12^{10} }{12^{4}}\right)^{-1} }\)

\(\large\color{black}{ \displaystyle \frac{12^{4} }{12^{10}} }\)

Answer 7

and then \(=1/12^{10-4}=12^6\)

Answer 8

thanks

Answer 9

I mean 1/12\(^6\)

Answer 10

(or instead of 1/12\(^6\), you can write 12\(^{-6}\))