pls factor this with solutions 12p^2q - 78pq^2-270q^3

Question

anonymous · Answer

You just posted this?

anonymous · Answer

it was supposed to be factored haha

anonymous · Answer

Oh, got you. Alright. So we need to factor this..?

$$p=\frac{ 78q^2\pm 138 \sqrt{q^4} }{ 24q }$$

anonymous · Answer

It would then factor down to ...

$$p=9q$$

anonymous · Answer

no no just the eqation

anonymous · Answer

12p^2q - 78pq^2-270q^3 <-- this one

anonymous · Answer

OHHHH xD I was solving it with particular method then factoring it.. Okay. My bad, alright hold on. I can get you the proper answer :P

anonymous · Answer

okay okay

anonymous · Answer

So we're going to factor the following:

$$12p^2q - 78pq^2-270q^3$$

First, you want to factor the common terms out of the equation.

factor 6q out of

$$12p^2q - 78pq^2-270q^3$$

Leaving you with..

$$6q(2p^2-13pq-45q^2)$$

Giving you the final answer of..

$$6q(2p+5q)(p-9q)$$