Question

pls factor this with solutions 12p^2q - 78pq^2-270q^3

Answer 1

You just posted this?

Answer 2

it was supposed to be factored haha

Answer 3

Oh, got you. Alright. So we need to factor this..?

\[p=\frac{ 78q^2\pm 138 \sqrt{q^4} }{ 24q }\]

Answer 4

It would then factor down to ...

\[p=9q\]

Answer 5

no no just the eqation

Answer 6

12p^2q - 78pq^2-270q^3 <-- this one

Answer 7

OHHHH xD I was solving it with particular method then factoring it.. Okay. My bad, alright hold on. I can get you the proper answer :P

Answer 8

okay okay

Answer 9

So we're going to factor the following:

\[12p^2q - 78pq^2-270q^3\]

First, you want to factor the common terms out of the equation.

factor 6q out of

\[12p^2q - 78pq^2-270q^3\]

Leaving you with..

\[6q(2p^2-13pq-45q^2)\]

Giving you the final answer of..

\[6q(2p+5q)(p-9q)\]