Question

@BloomLocke367

Answer 1

a = 1, b = 6, c = 5

Solve using the Quadratic Formula

Answer 2

ANS:
-5 or -1
-(2/5) or -(1/2)
-(2/5) or -(1/3)
5 or 1

Answer 3

okay and you already know the quadratic formula. \(x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Answer 4

\[\frac{ -6 \pm \sqrt{6^2 - 20} }{ 2}\] This would be a simpler form of the formula given the terms. I just eliminated the a = 1 and added the -4(5).

Answer 5

yep. now square the 6 under the radical

Answer 6

I'm sure you know what \(6^2\)is right?

Answer 7

\[\frac{ -6 \pm 3.5 }{ 2 }\]

Answer 8

The problem being, when I solve, I get 4.75 and -1.25, which if you look at the answers above, these are not it.

Answer 9

okay, first off, how did you get 3.5?

Answer 10

\(6^2=36\) so you would take \(\large\sqrt{36-20}\). What is 36-20?

Answer 11

\[\frac{ -6 \pm \sqrt{36 - 20}}{ 2} = \frac{ -6 \pm \sqrt{12} }{ 2 }\] \[\sqrt{12} = 3.5\]

Answer 12

36-20 does not equal 12. double check your math there

Answer 13

@Compassionate

Answer 14

\[\frac{ -6 \pm 16 }{ 2} = 5 \space or \space -10\]

Answer 15

ANS:
-5 or -1
-(2/5) or -(1/2)
-(2/5) or -(1/3)
5 or 1

Answer 16

you forgot something. \(\large\sqrt{16}=?\)

Answer 17

because you have \(\LARGE \frac{-6\pm\sqrt{16}}{2}\)

Answer 18

right. Even if you take 4
\[\frac{ -6 \pm 4 }{ 2 } = -2/2 = -1 \space or -5\]

Answer 19

there it is. I was a mess.

Answer 20

I'm giving the computer back to my girlfriend. Thanks!

Answer 21

hahaha it's alright :) do you need any other help? I'll be happy to help. Sometimes you just have to slow down a bit and think xp

Answer 22

you're welcome! :D you know where to find me if needed.