Question

Find the value of the discriminant. Describe the number and type of roots.

4x^2 - 6x + 2 =0

I tried it at least, and I got 4 for the discriminant... That's all I know, and I don't even know if it's right. So please, help me.. I suck at math

Answer 1

\(\huge\color{reD}{\rm b^2-4ac}\) `Discriminant`
you can use this to find if the equation is factorable or not
if ` b^2-4ac > 0` then there are 2 real zeros

if ` b^2-4ac = 0` then there is one real root
if ` b^2-4ac < 0` then you will get two complex roots (no -x-intercept)

Answer 2

Ok, so i did do that, and i got four for the discriminant. Does that mean that the root is 2, and that it is a complex root?

Answer 3

4 is greater than or less than 0 ?

Answer 4

Um.. I think...? I'm very unsure about math. It is not my forte. I just got very confused..

Answer 5

so 4 is greater than 0 right ?
4 is bigger than 0 ?

Answer 6

yes

Answer 7

do b^2-4ac = 4
4>0 now read my first comment

Answer 8

if b^2-4ac> 0 then how many roots would you have ?

Answer 9

Two real zeros one, correct?

Answer 10

oh, sorry didnt see the second comment. and uh, im not sure

Answer 11

yes right if you get positive number then you get 2 solutions

Answer 12

remember
if discriminant = 0 then one solution
if discriminant is a negative number then no real solution
and if discriminant is positive number then 2 solutions

Answer 13

ohh, that makes sense! I never learned anything about roots. so since its positive, it will have 2 solutions, in other words, 2 roots. correct?

Answer 14

yes right!

Answer 15

Awesome! Thank you so much for your time and help. I really appreciate it.

Answer 16

my pleasure :=) good work!!