Let v1 = (2, -6) and v2 = (-4, 7).
Compute the unit vectors in the direction of |v1| and |v2|.
And can anyone double check if this graph is right? Draw and label v1, v2, and v1+v2.
https://gyazo.com/ca330d1301b8dd28e0cdfa3e72f6443c

Question

Let v1 = (2, -6) and v2 = (-4, 7).
Compute the unit vectors in the direction of |v1| and |v2|.
And can anyone double check if this graph is right? Draw and label v1, v2, and v1+v2.
https://gyazo.com/ca330d1301b8dd28e0cdfa3e72f6443c

alex_mattucci · Answer

Your graph is looking great!

alex_mattucci · Answer

is that all?

anonymous · Answer

Compute the unit vectors in the direction of |v1| and |v2|. 
What exactly is this question trying to find?

solomonzelman · Answer

$\large\color{black}{ \displaystyle \frac{\vec{V_1} }{\left|\left| \vec{V_1}\right|\right|} }$

solomonzelman · Answer

This is the unit vector (with magnitude 1) in direction of  $\vec{V_1}$

anonymous · Answer

How would you plug in the vector v1 into this equation to find a value?

solomonzelman · Answer

Note: V$_1$ with two bars on each side, means "magnitude of V$_1$.

solomonzelman · Answer

You want  units vecotrs with the same directions as $\vec{V_1}$ and $\vec{V_2}$, right?

solomonzelman · Answer

|dw:1442448091015:dw|

solomonzelman · Answer

that means that if you take each component and divide by this magnitude, you get a unit vector in same direction.

solomonzelman · Answer

$\left|\vec{V_1}\right|=\sqrt{(-2)^2+(6)^2{\color{white}{\large|}}}$

solomonzelman · Answer

I mixed it up, 2, and -6.
For magnitude that doesn't matter though.
you still get 2√10

solomonzelman · Answer

|dw:1442448470003:dw|