Question

WILL MEDAL Solve x3 = 64/27.

Answer 1

64/81=x

Answer 2

@firedupme did u get it

Answer 3

??!

Answer 4

hold on

Answer 5

\[x ^{3} =\frac{ 64 }{ 27 }\]

so take cube root to find x

\[\sqrt[3]{x ^{3}} = x = \sqrt[3]{\frac{ 64 }{ 27}} = \frac{ \sqrt[3]{64} }{\sqrt[3]{27} }\]

Answer 6

@MrNood is correct. He got it to it before me :P good job.

Answer 7

@moha_10
you have misread the question - it is x^3 - NOT 3x

Answer 8

im pretty sure my answer is wrong

Answer 9

im terrible at these questions

Answer 10

alright is my mistake sorry @MrNood

Answer 11

the answers are
±8 / 3
8 / 3
±4 / 3
4 / 3

Answer 12

@MrNood im really bad at these so just bare with me.

Answer 13

I wrote all but the last step above

the answer is
\[x= \sqrt[3]{64}\div \sqrt[3]{27}\]

it turns out that those 2 numbers are VERY easy to get the cube root

use your calculator - or just use some common sense

what number is cubed to make 64?
what number is cubed to make 27?

Answer 14

8

Answer 15

8/3

Answer 16

what about the ±?

Answer 17

8 cubed = 8x8x8 = 492

Answer 18

so the answer is 8/3

Answer 19

@MrNood

Answer 20

PLZ

Answer 21

I just showed you that 8 cubed is NOT 64 so therefore cuberoot of 64 is not 8

so 8 is not in the answer

Answer 22

so it would have to be 4/3.
i just don't get the ±

Answer 23

so is it ±4/3 or just 4/3
?

Answer 24

as an example

\[\sqrt{4} =\pm 2\]

BECAUSE -2 x -2 = 4 AND 2 X 2 = 4

is this true for CUBE root?

Answer 25

yes

Answer 26

so ±4/3

Answer 27

right?

Answer 28

Nope that waws wrong ,,,, fun