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Chemistry 15 Online
OpenStudy (anonymous):

desperate need of help!!!! will medal and fan!! In the reaction K2CrO4(aq) + PbCl2(aq) --> 2KCl(aq) + PbCrO4(s), how many grams of PbCrO4 will precipitate out from the reaction between 500.0 milliliters of 3.0 M K2CrO4 in an excess of PbCl2? 1.5 grams 3.0 grams 480 grams 150 grams

OpenStudy (anonymous):

@TheSmartOne @angrybadger.exe @Ahobart12160 @Luigi0210 @mathstudent55 @ChiefArnav

OpenStudy (anonymous):

no idea

OpenStudy (anonymous):

@TINY10207 @Mtalha2 @THEHELPER123

OpenStudy (anonymous):

sorry dont know

OpenStudy (anonymous):

@H3LPN33DED @Koikkara @robtobey @whpalmer4 @toxicsugar22 @youngnephew34 @inkyvoyd @OpTicRebekah @Jaynator495 @Jackky @Justmeneedinghelp @jeremy12345 @Lost??? @loomely @hannah120899 @fantasywolfpack

TheSmartOne (thesmartone):

@Australopithecus @chmvijay @matt101 @aaronq can help you better

TheSmartOne (thesmartone):

also @JFraser can help

OpenStudy (anonymous):

You will find your answer on this website https://ca.answers.yahoo.com/question/index?qid=20110216112647AAwvziD

OpenStudy (anonymous):

@Mtalha2 could you please take a screenshot of it, it's blocked on my school computer :(

OpenStudy (anonymous):

@TheSmartOne thank you!!

TheSmartOne (thesmartone):

the screenshot of that: http://prntscr.com/8hgy81

OpenStudy (anonymous):

for some reason that link is blocked of your screenshot. could you just add it as a file? sorry

OpenStudy (anonymous):

moles K2CrO4 = 0.500 L x 3.0 M=1.50  K2CrO4 + PbCl2 = PbCrO4 + 2 KCl  the ratio between K2CrO4 and PbCrO4 is 1 : 1  moles PbCrO4 = 1.50 mol x 323.2 g/mol=485 g

OpenStudy (anonymous):

@Mtalha2 can u still help!

OpenStudy (anonymous):

Yeah sure

OpenStudy (anonymous):

could u just take a screenshot of that page. add it as a file please @Mtalha2

OpenStudy (anonymous):

Lol I already send u what's there

OpenStudy (anonymous):

@Mtalha2 yeah the link but I'm on my school computer so the links blocked, I was wondering if u could take a screenshot of the answer please and add it as a file!! I will medal & fan u

OpenStudy (anonymous):

OpenStudy (anonymous):

Lol here you go!!

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