Advanced PHYSICS question. SATELLINE in SPACE (((FORCES, ACCELERATIONS etc...)))

Question

idku · Answer

Scientists want to place a 2700 kg satellite in orbit around Mars.
They plan to have the satellite orbit a distance equal to 2.3 times
the radius of Mars above the surface of the planet. Here is some
information that will help solve this problem:

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$\large \rm m_{mars} = 6.4191 \times  10^{23} kg $
$\large \rm r_{mars} = 3.397 \times  10^6 m $
$\large \rm G = 6.67428 \times  10^{-11} {~}(N-m^2)/kg^2 $

idku · Answer

1)   What is the force of attraction between Mars and the satellite?

idku · Answer

((I dissapear from the site, due to this site's faultiness when it comes to connecting. Apologize ))

ganeshie8 · Answer

you may use newton's law of gravity : 
$$F = G \dfrac{m_1m_2}{r^2}$$

idku · Answer

G × (2700kg  ×   6.4191×10$^{23}$kg) / (3.397 × 10$^{6}$m)

and I will plug my G of course...

idku · Answer

3.41 N is what I get.

idku · Answer

wrong_:

idku · Answer

6.67428×10^(-11)• (2700 ×   6.4191×10^(23)) / (3.397 × 10^(6))

this is what I plugged into wolfram, and got 3.41

idku · Answer

oh... I am the dumpest on the planet r^2

ganeshie8 · Answer

Yes, and careful, r is the distance between centers of objects

idku · Answer

Wait so r is not that r_mars ?

ganeshie8 · Answer

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