The solubility product of BaSO4 at 25 C is 10^-9. What would be the concentration of H2SO4 necessary to precipitate BaSO4 from a solution of 0.01 M Ba+2 ions
I am calculating it to be \(\sf 10^{-7}\)
But the answer says \(\sf 10^{-6}\)
Any idea @Photon336 ?
@Rushwr ?
\[ksp = x ^{2} = [Ba ^{2+}][So4^{2-}]\] \[\frac{ [10^-9] }{ [0.01] } = 10^{-7}\] by eyeballing this I believe that's when it's saturated. so it would have to be more than that 10^-6 @abishar I agree with @rushwr
Oh Right!!!!!!!!!!!!!
I think that's the concentration when it's saturated that means that it won't precipitate at this concentration , @rushwr what do you think?
I get it now, it should be anything greater than \(\sf 10^{-7}\) and hence \(\sf 10^{-6}\)
Thanx both of you c: Appreciate it..
Absolutely, anytime
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