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Physics 12 Online
OpenStudy (anonymous):

In his famous race, a hare runs for a while, takes a nap, and then resumes running until he reaches the finish line. His total displacement from start to finish is 5.0 m east and 12 m north. The hare's total race time, including the time of napping, is 28 minutes. What is the hare's average speed in meters per minute?

OpenStudy (abhisar):

Average speed = Total distance/Total time.

OpenStudy (abhisar):

Total distance here will be (5+12)m and total time is given in the question. NOTE:- Even the time he spent while sleeping will be considered.

OpenStudy (anonymous):

would it be 0.55?

OpenStudy (anonymous):

@Abhisar

OpenStudy (abhisar):

How are you doing?

OpenStudy (abhisar):

Average speed = 17/28 meters/min

OpenStudy (anonymous):

0.607142857143 thats what i got as my answer @Abhisar

OpenStudy (abhisar):

That's \(\checkmark\) this time..

OpenStudy (anonymous):

but they dont have that as an answer choice so i dint know what to choose @Abhisar

OpenStudy (anonymous):

0.55 m/min 1.2 m/min 0.92 m/min 0.46 m/min This is all they have so would it be 1.2?

OpenStudy (abhisar):

All right. this means the rabbit traveled in a straight line. In this case the total distance will be as following|dw:1442588022634:dw|

OpenStudy (abhisar):

So the distance is represented by the red line AB. AB= \(\sf \sqrt{5^2+12^2}\) Now, do the same steps, divide the distance with total time.

OpenStudy (abhisar):

Getting it?

OpenStudy (anonymous):

Now i got it thanks man!

OpenStudy (abhisar):

You're welcome

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