Question

A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2.



22.5 meters



50.7 meters



100 meters



110 meters



152.45 meters

Answer 1

What have you tried so far?

Answer 2

22.5

Answer 3

let the depth of the well is d

Now , Using second equation of motion

d = u * t + 0.5 g * t^2

100 + d = 0 * 5 + 0.5* 9.8 * 5^2

solving for d

d = 22.5 m

the depth of the well is 22.5 m