Question

A binomial experiment has 5 trials in which p = 0.7. What is the probability of getting at least 2 successes?

Answer 1

So, I thought that I understood how to do this, but I'm getting something wrong!
P(2)=\[_{5} C _{2} (.7)^{2} (.3)^{3}=.1323\]
P(3)=\[_{5}C _{3} (.7)^{3} (.3)^{2}=.3087\]
and added they equal .441

Answer 2

The possible answers are:
0.9692
0.4417
0.4683
0.7481

Answer 3

"At least 2 successes" out of "5 trials". You're missing \(P(X=4,5)\).

Answer 4

Okay, let me work that out real quick!

Answer 5

Awesome, so that would be .9692! Thank you!!

Answer 6

That's right.

Answer 7

yw