I really need help I don't have a math teacher so I'm trying learn this on my on so please someone help What is 16 5/4 in simplest form? There more questions but I'm putting the file down in the comments.
simplest form is a bit vague. But as a rule, if you see a fraction like \[ \frac{5}{4}\] where the top is bigger than the bottom, that is an "improper fraction" which means people would rather see it written as a mixed number can you write 5/4 as a mixed number?
i guess
5/4 means divide 4 into 5, plus a remainder that you "put over" 4
if you divide 4 into 5 it's 0.8
that is 4/5 = 0.8 in other words you did 5 divided into 4
either I'm stupid or i just don't get what you're saying
Can you post a copy of the question?
yes hold on
What he's trying to say is you need to do the problem 5 divided by 4 as a starter
oh, that is different from what I thought 5/4 is an exponent
Oh same here :/
5 divided by 4 is 1.25
Ok so basically this problem is asking what is 16 to the power of 1.25 right @phi
yes, 5/4 = 1.25 but that is not the problem we have to solve here the way we solve this is write the problem as \[ \left( 16^\frac{1}{4}\right)^5 \] the 1/4 power means the "fourth root"
Right
to find the 4th root (which is generally hard to do, but possible here) we should factor 16 into 2*2*2*2 = \(2^4\)
do you see that 2 times itself 4 times is 16 ?
81?
so we write 16 as 2^4 \[ \left( 16^\frac{1}{4}\right)^5 = \left( (2^4)^\frac{1}{4}\right)^5\]
now use the rules of exponents we use this rule \[ (a^b)^c = a^{bc} \] on \[ (2^4)^\frac{1}{4} \] can you do that ?
I'm stupid and lost
do 2x2x2x2
right?
the rule \( (a^b)^c = a^{bc} \) means if you have an exponent b and another exponent c , we can multiply them
you "match the pattern" \[ (a^b)^c = a^{bc} \\ (2^4)^\frac{1}{4} \]
we could do 2*2*2*2 but we don't want to (because if we use the exponent rule we will get a simpler answer)
look at these two things \[ (a^b)^c = a^{bc} \\ (2^4)^\frac{1}{4} \] do you see you can match a with 2, and 4 with b, and 1/4 with c ?
the idea is we can rewrite (2^4)^(1/4) using that rule \[ 2^{4 \cdot \frac{1}{4} }\]
i see numbers that's makes no sense to why the hell letters are in a math problem and we are talking about 16 and a 5/4 so where in the world did a 2 and a 1 come form
I'm sorry that im getting mad and rude but i've been doing this all day and been have to learn this on my on
the letters are how to show a "rule" we could use words, but it gets confusing. anyway, we started with \[ 16^\frac{5}{4} \] we use a "rule" to write that a different way \[ (16^\frac{1}{4})^5 \] before going on, do you know what 1/4 * 5 is ?
1/4
\[ \frac{1}{4} \cdot 5 = ?\] (as an improper fraction)
sorry 1.25
ok, but not as a decimal. what about as a fraction ?
no i dont i just know what it is as a decimal because my phone told me
when you multiply fractions, you multiply top times top and bottom times bottom (if a number (like the 5) has no "bottom" , assume it is 1) now try again \[ \frac{1}{4} \cdot 5=?\]
5/4
yes. the reason we want to know that is we can say \[ \frac{5}{4}= \frac{1}{4} \cdot 5 \] and vice versa
and there is a rule that let's us write \[ 16^\frac{5}{4} = (16^\frac{1}{4})^5 \]
so now i know where you got 1/4
if you see \[ (16^\frac{1}{4})^5\] you should remember you are allowed to write it as \[ 16^\frac{5}{4} \] we need to be able to between these two different ways
so far we have \[ (16^\frac{1}{4})^5\] the next thing is to know we can write 16 as 2*2*2*2 (this is the hard part, knowing that. but now you do. (don't forget) )
do you know how to use the "short-cut" way using exponents to write 2*2*2*2 ? in other words that is 2^?
2*2*2*2 is 2 to some power (some exponent) do you know what little number we should put in the upper right of 2 so that it means 2*2*2*2 ?
the answer 17 1/4
do you know \(2^1 = 2 \) and \( 2^2 = 2\cdot 2\) and \(2^3 = 2\cdot 2\cdot 2\) ?
yes
ok, so how do we write \[ 2\cdot 2\cdot 2\cdot 2= 2^? \]
2 to the 4 power
ok, so we know 16= 2*2*2*2 and that is 2^4
\[ (16^\frac{1}{4})^5 \\ ((2^4)^\frac{1}{4})^5 \]
now let's use the rule on \[ (2^4)^\frac{1}{4} \] remember we can multiply the exponents ?
so I multiply 2^4 by 1/4?
you multiply the exponents , so just 4*1/4 and that is the new exponent
1
that means \[ (2^4)^\frac{1}{4} = 2^1 \]
so now we have this \[ (16^\frac{1}{4})^5 \\ ((2^4)^\frac{1}{4})^5 \\ (2^1)^5 \] notice we can use the rule again to multiply the exponents on the last line
(2^1)5 is 10
no, not 10 it is (2^1)^5 i.e. \( (2^1)^5\) multiply the exponents (that means 1 and 5)
5
yes, and that means 5 is the new exponent. so (2^1)^5 = 2^5 ok ?
okay i get that
they may want you to multiply that out for the final answer what is 2 times itself 5 times ?
32
yes, that is the answer
thank you so much for helping me and last question are you a math teacher?
no
you need to be
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