Question

..

Answer 1

I think the right answer to this is .12

Answer 2

So for linear approximation we use ummm...\[\large\rm f(x)\approx f(x_o)+\color{orangered}{f'(x_o)(x-x_o)}\]Something like that, ya?
Where the orange stuff is our error.

Wait.. is that the error? Hmmm thinking

Answer 3

Im not sure this problem is very confusing

Answer 4

Yes it is +_+

So the error in the output \(\large\rm \Delta y \) ummm...
ya ya ya, should be \(\large\rm f'(x_o)\color{green}{\Delta x}\),
where Delta x is the distance between our base point x_o and x.
\(\large\rm \Delta y\approx f'(x_o)\color{green}{(x-x_o)}\)

So our base point is x=1.
And we're drifting 0.001 away from that.
\[\large\rm \Delta y\approx f'(1)(0.001)\]

Answer 5

Were you able to come up with a formula for Surface Area of a cube? :)
And its derivative?

Answer 6

No I was not

Answer 7

Take a cube, call the side length x.
Since it's a cube, all side lengths are the same.
The area of one face will be x*x, ya?

So the total surface area will be the area of all 6 panels of the cube.
\(\large\rm A=6x^2\)

Answer 8

Wait wait, then how were you able to come up with .12? LOL
Just straight up guessing? >.< Buhaha, Cam cam, come on!!

Answer 9

Haha yes it was a guess but it made sense

Answer 10

So your derivative is \(\large\rm A'=12x\).
Mmm k.

Answer 11

And your error approximation for the output \(\large\rm \Delta y\) is going to be\[\large\rm =A'(x_o)\Delta x\]Our base point is x=1.
And our delta is the distance between the x's, 0.001.

Answer 12

Ok

Answer 13

\[\large\rm =A'(1)(0.001)=?\]

Answer 14

1X10^-3

Answer 15

What? 0_o
Plug 1 into A'(x) and then multiply that value by 0.001

Answer 16

Oooo .12?

Answer 17

Hmm that's not what I'm getting.. lemme see..

Answer 18

\[\large\rm =\color{orangered}{A'(1)}(0.001)=\color{orangered}{12(1)}(0.001)=12(0.001)=0.012\]

Answer 19

Is that one of our options? :o
Hopefully we're doing this right <.<

Answer 20

Yes it is!!

Answer 21

Wait no
its .12

Answer 22

What do the other options look like? XD

Answer 23

.02 .003 and none of the above

Answer 24

Hmm :p

@ganeshie8 @dan815

Answer 25

Ill just put in .12 and hope thats the answer

Answer 26

Thank you for the help!

Answer 27

ya sorry :c

Answer 28

Its okay thanks for the help!!