Question

Prove SSS theorem.
Please, help.

Answer 1

@zzr0ck3r

Answer 2

@dan815

Answer 3

I can help but wats the problem?

Answer 4

Prove SSS theorem, that is the problem.

Answer 5

Oh I thought u had to prove two triangles similar using sss

Answer 6

\(\triangle ABC \) and \(\triangle A'B'C'\) such that AB = A'B', AC = A'C', BC = B'C'.
Prove that \(\triangle ABC \cong \triangle A'B'C'\)

Answer 7

I can't help on proving theorem itself sorry

Answer 8

Hmmm

Answer 9

It's ok, friend. Thanks for being here.

Answer 10

Sorry can't help

Answer 11

SSS is a postulate

Answer 12

right, I don't think you prove this one.

It would be like proving The Axiom of Choice without one of its equivalents.

Answer 13

Thanks for replying, but yes, we are and I have it done.

Answer 14

@oldrin.bataku @zzr0ck3r , this course is modern geometry. We learn how to prove a theorem (and SSS is a theorem, not postulate). The course is to train high school teacher how to teach geometry.

Answer 15

ahh, I never took geometry but when I googled it, it seemed like it was not something you prove.

Answer 16

SSS is a postulate in the original formulation of Euclidean geometry: https://en.wikipedia.org/wiki/SSS_postulate

depending on what alternative axiomatization you use for your modern geometry course, sure, you can prove it from that alternative foundation, but without stating that before it is only natural to assume we're talking about classical Euclidean geometry. it is impossible to even answer your question without your axiomatization anyways so this question as it stands is ill-posed and impossible to answer