Question

Help with exponents!

(x^4)^{-3} x 2x^4

Answer 1

\[(a^x)^y = a^{xy}~~~~~~~~~a^x \times a^y = a^{x + y}\]

Answer 2

Sorry i meant 1/x^12 x 2x^4

Answer 3

hmmm v???

Answer 4

No i wrote x

Answer 5

okay see(x^4)^{-3} = x^{-12}

Answer 6

Yes...

Answer 7

now u got
\[x^{-12} \times 2 \times x^4\]

so use a^x + a^y = a^{x + y}

Answer 8

x^{-8}

Answer 9

question is
\[(x^4)^{-3} \times 2x^4\]

Answer 10

Yes

Answer 11

so u got 2*x*{-8}
u can write it as 2/(x^{}8) or just 2x^{-8}

Answer 12

I dont understand

Answer 13

u know
\[\frac{ 1 }{ a^x } = a^{-x}\]

Answer 14

so here u having
\[2x^{-8}\]
just leave it tht way :)

Answer 15

But why do i need to combine them? R they like terms and, if so, why?

Answer 16

these are the exponents rules when we multiply same bases we should `add` exponents \[\huge\rm x^m \times x^n=x^{m+n}\]
and when we divide same base , `subtract` their exponents \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]

Answer 17

\(\color{blue}{\text{Originally Posted by}}\) @rishavraj
u know
\[\frac{ 1 }{ a^x } = a^{-x}\]
\(\color{blue}{\text{End of Quote}}\)
if there is negative exponents we should flip the fraction when we flip the fraction sign of the exponent would change

Answer 18

that's for negative exponent rule he gave u^^^^

Answer 19

\(\color{blue}{\text{Originally Posted by}}\) @calculusxy
But why do i need to combine them? R they like terms and, if so, why?
\(\color{blue}{\text{End of Quote}}\)
like base

Answer 20

So the 2 doesn't matter? @Nnesha

Answer 21

multiply the coefficient
x is same as 1x \[\huge\rm1 x^{-12} \times 2x^4=(1 \times 2)x^{-12+4}\]

Answer 22

Okay so 2x^4 has two terms right? Since 2 is being multiplied with x^4, the two is one term and x^4 is another?

Answer 23

sorry for late reply not getting notification so plz tag the username :=)
no 2x^4 is only one term not two
terms: number or variable that are separated by `+` or `-` sign

Answer 24

so 2x^4 is only one term
when we multiply we should focus on the base
when you `ADD or subtract ` like terms u just have to deal with the coefficients like
\[2x+3x=(2+3)x\]
but when we multiply same bases we should `add` their exponents and multiply the coefficien\[\huge\rm \color{Red}{1}x^m · \color{blue}{1}x^n=(\color{red}{1} ·\color{blue}{1})x^{m+n}\]ts as well

Answer 25

coefficient *