Question

Help with exponents!


@hartnn

Answer 1

\[\huge (2v)^2 \times 2v^2\]

Answer 2

\[\large (2v)^2 = 2^2 \times v^2 = 4v^2\]
\[\large 4v^2 \times 2v^2 = 8v^2 \]

or does it equal to\[\large 8v^4\]

Answer 3

\[\huge\rm (ab)^m =a^m b^m\] apply this exponent first
both number in the parentheses are raising to the m power

Answer 4

looks good!

Answer 5

So which one does it equal to?

Answer 6

\[\large 8v^2 \] or \[\large 8v^4\]

Answer 7

ohh i see
well when we multiply same bases we should `ADD` their exponents

Answer 8

oh okay so it is \[8v^4 \] right?

Answer 9

remember it's not `combine like terms` \[2x+3x=(2+3)x\] when we add/subtract like terms variable stay the same
but when we multiply them we should add their exponents

Answer 10

yes right

Answer 11

I have another question @Nnesha

Answer 12

okay :=)

Answer 13

when you `ADD or subtract ` like terms u just have to deal with the coefficients like
\[2x+3x=(2+3)x\]
but when we multiply same bases we should `add` their exponents and multiply the coefficient\[\huge\rm \color{Red}{1}x^m · \color{blue}{1}x^n=(\color{red}{1} ·\color{blue}{1})x^{m+n}\]

Answer 14

\[\huge \frac{ 2x^2y^4 \times 4x^2y^4 \times 3x }{ 3x^{-3}y^2 }\]

Answer 15

ayoooXD

Answer 16

I guess you forget what he/she did there lol

Answer 17

multiply the coefficients and add the exponent of the same base

Answer 18

\[\huge \frac{ 2x^2y^4 \times 4x^2y^4 \times 3x }{ 3x^{-3}y^2 }\]
can be written as \[\frac{ (2·4·3)(x^2·x^2·x)(y^4·y^4) }{3x^{-3}y^2 }\]

Answer 19

and x is same as x^1

Answer 20

\[\large \frac{ 16x^5y^8 }{3x^{-3}y^2 } = \frac{ 16x^8y^6 }{ 3 }\]

Answer 21

(2 times 3 times 4) isn't equal to 16 :=) x^8 and y^6 is correct

Answer 22

sorry 24

Answer 23

yes 24/3 simplify
done!

Answer 24

8

Answer 25

that's it great job!

Answer 26

Thank you! If i need more help can i mention you...?

Answer 27

sure!