Quadratic simultaneous equation PLEASE help me
\[y= x-4\] \[2x ^{2} -xy = 8\] Give your answer in the form a±b sqrt(c)
replace the y in the second equation by x - 4 to form a quadratic in x
It says I have to use elimination though?
Should I make y the subject of both of them and then minus them?
Multiply the first equation by x
@nosnip
So you get \[x ^{2} - xy - 4x = 0\] \[2x ^{2} - xy - 8 = 0\] Is that right?
And then you have to minus them?
What you want to do is setup the equations in a way where you can combine both together and eliminate the xy term . I try to setup to add rather than subtract
So if the plus and minus signs were all reversed and x^2 and 2x^2 were both negative owuld that be better?
Got it thankyou so much :)
What DID you get btw?
Well it was a "prove that..." question and I got x^2 +4x - 8 which is what we had to prove so thanks :)
I thought you had to solve for x in the form a±b sqrt(c)
No that was a mistake I have to prove
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