Question

A dice is rolled six times.
One, two, three, four, five and six appears on consecutive throws of dices.
How many ways are possible having 1 before 6?

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{ A dice is rolled six times. }\hspace{.33em}\\~\\
& \normalsize \text{ One, two, three, four, five and six appears on consecutive throws of dices.}\hspace{.33em}\\~\\
& \normalsize \text{ How many ways are possible having 1 before 6?}\hspace{.33em}\\~\\
\end{align}}\)

Answer 2

if 1 occurs on the first throw ether are 5! ways . Agreed?
I'm never 100% confident on these counting questions!!

Answer 3

ok

Answer 4

so I guess we have to consider the scenario when occurs on the second throw.
when 6 occurs on the first throw we have to discount these arrangements

Answer 5

* when 1 occurs

Answer 6

so that is -4!

Answer 7

negative 4! ?

Answer 8

No sorry - we just ignore those

Answer 9

if no 6 on first throw there are 4 * 4! ways right?

Answer 10

how does that come

Answer 11

is the answer (5!)^2 ?

Answer 12

well you have any number between 2 and 5 on first throw and there are 4! arrangements of the other 4

Answer 13

in book it is given as 6!/2=360

Answer 14

sry i did a silly mistake
well-


like this make cases nd then u get tota ways= 5!+4*4!+3*4!+2*4!+1*4!=360