Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (ksaimouli):

limit

OpenStudy (ksaimouli):

\[(1/x- 1/5)/(x-5)\]

OpenStudy (ksaimouli):

as x-> 5

OpenStudy (amistre64):

what are the degrees of the top and bottom?

OpenStudy (ksaimouli):

1

OpenStudy (amistre64):

-1 and 1 do you recall your rules for degrees?

OpenStudy (ksaimouli):

What do you mean by degree? You mean power of x?

OpenStudy (amistre64):

yes

OpenStudy (amistre64):

might only work for proper polynomilas tho simplify by multiplying top and bottom by 5x

OpenStudy (ksaimouli):

5-x/(5x^2-25x)

OpenStudy (amistre64):

(5-x)/(5x(x-5)) -(x-5)/(5x(x-5)) -/(5x)

OpenStudy (amistre64):

-1/(5x)

OpenStudy (ksaimouli):

-1/25, got you

OpenStudy (ksaimouli):

or we could use L'hospitals rule right?

OpenStudy (anonymous):

Or just the definition of the derivative.

OpenStudy (amistre64):

the fractiony top part tends to play havok with derivatives, but its worth a shot if you are allowed to use it

OpenStudy (amistre64):

1/x derives to -1/x^2 ... and the limit thing is usually x to 0 tho

OpenStudy (ksaimouli):

By looking at it, how did you come up to multiply by 5x?

OpenStudy (amistre64):

/x and /5 have 5x as a common denomto clear the fractions

OpenStudy (ksaimouli):

Got you! thanks

OpenStudy (amistre64):

lhop has no issues with this

OpenStudy (amistre64):

good luck

OpenStudy (anonymous):

For \(h\to0\), where \(h\) represents the difference between two values of the independent variable. You can make a small modification to that definition to arrive at the derivative at a point: \[f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}~~\implies~~f'(c)=\lim_{x\to c}\frac{f(x)-f(c)}{x-c}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!