can someone help me on substituting and eliminating systems of equations?! I'm so confused
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jimthompson5910 (jim_thompson5910):
Post the full problem please
OpenStudy (bieber896):
x=3y-8
5y=19+4x
OpenStudy (bieber896):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
since x is fully isolated, you can replace the x in the second equation with 3y-8
so `5y=19+4x` turns into `5y=19+4(3y-8)`
jimthompson5910 (jim_thompson5910):
do you see how to solve for y?
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OpenStudy (bieber896):
5y=19+12y-32??
OpenStudy (bieber896):
but there's two ys
jimthompson5910 (jim_thompson5910):
get all the y terms to one side
so subtract 12y from both sides to get the y terms to the left side
OpenStudy (bieber896):
-7y=19+(-32)?
jimthompson5910 (jim_thompson5910):
good, then combine like terms on the right side
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OpenStudy (bieber896):
-7y=-13
jimthompson5910 (jim_thompson5910):
what comes next
OpenStudy (bieber896):
divide both sides by -7?
jimthompson5910 (jim_thompson5910):
correct
jimthompson5910 (jim_thompson5910):
\[\Large -7y = -13\]
\[\Large \frac{-7y}{-7} = \frac{-13}{-7}\]
\[\Large y = \frac{13}{7}\]
Notice how the two negatives divide to make a positive result
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OpenStudy (bieber896):
so y=1.85
jimthompson5910 (jim_thompson5910):
I'd leave it as a fraction because the decimal result is only an approximation
OpenStudy (bieber896):
oh ok
OpenStudy (bieber896):
so then do I plug that in to the next equation?
jimthompson5910 (jim_thompson5910):
yes, you'll plug that into `x=3y-8` to find x
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OpenStudy (bieber896):
so x=-2 3/7
jimthompson5910 (jim_thompson5910):
or x = -17/7
so the solution as an ordered pair is \(\LARGE \left( -\frac{17}{7}, \frac{13}{7}\right)\)
OpenStudy (bieber896):
ok thanks so much ! can we just do one more?!
OpenStudy (anonymous):
yes
jimthompson5910 (jim_thompson5910):
sure
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OpenStudy (bieber896):
y=3x+3
y=2x+1
jimthompson5910 (jim_thompson5910):
y is equal to 3x+3
AND
it's also equal to 2x+1
jimthompson5910 (jim_thompson5910):
since y is equal to those two things, we can set the two equal to each other
basically we're performing a substitution
jimthompson5910 (jim_thompson5910):
y=2x+1
3x+3 = 2x+1 ... replace y with 2x+1
solve for x to get x = ??
OpenStudy (bieber896):
so do I have to get rid of one of the variables?
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OpenStudy (anonymous):
isolate your x
jimthompson5910 (jim_thompson5910):
move the 2x over
you do this by subtracting 2x from both sides
OpenStudy (anonymous):
x=___
OpenStudy (bieber896):
1x+3=+1
jimthompson5910 (jim_thompson5910):
now subtract 3 from both sides to move that 3 to the right side
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OpenStudy (bieber896):
1x=-2
jimthompson5910 (jim_thompson5910):
which is the same as x = -2
OpenStudy (bieber896):
yup
OpenStudy (bieber896):
then plug it in
jimthompson5910 (jim_thompson5910):
now plug that into either equation to find y
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OpenStudy (bieber896):
so the solution is (-2,3)
OpenStudy (bieber896):
or -3 lol my bad
jimthompson5910 (jim_thompson5910):
yes it's (-2,-3)
OpenStudy (bieber896):
thank you both so much for your help @jim_thompson5910 @tekman1298