A student uses the quadratic formula to solve a quadratic equation and determines that one of the solutions is x equals negative seven plus square root of negative 99 end square root. What are the values of a and b if this solution is written in the form x = a + bi, where a and b are real numbers?
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OpenStudy (anonymous):
HELP PLEASE
OpenStudy (anonymous):
Bit of factoring is all that's required. You are given\[x=-7 + \sqrt{-99}\]Let's do some factoring using the rules of working with radicals.\[x=-7 + \sqrt{99}\sqrt{-1}\]You OK with that so far?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Good. Now, are you able to simplify \(\sqrt{99}\) ?
OpenStudy (anonymous):
3√ 11
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OpenStudy (anonymous):
right?
OpenStudy (anonymous):
Excellent. And do you know what \(\sqrt{-1}\) is?
OpenStudy (anonymous):
1
OpenStudy (anonymous):
No. The square root of -1 is the imaginary number i. It is referred to in the question. Have you seen it before?
OpenStudy (anonymous):
oh yes!
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OpenStudy (anonymous):
OK. So now your question looks like\[x=-7 + \sqrt{99}\sqrt{-1}\]\[x=-7+3\sqrt{11}i\]Compare this with\[x=a+bi\]What are the values of a and b?