A student uses the quadratic formula to solve a quadratic equation and determines that one of the solutions is x equals negative seven plus square root of negative 99 end square root. What are the values of a and b if this solution is written in the form x = a + bi, where a and b are real numbers?
HELP PLEASE
Bit of factoring is all that's required. You are given\[x=-7 + \sqrt{-99}\]Let's do some factoring using the rules of working with radicals.\[x=-7 + \sqrt{99}\sqrt{-1}\]You OK with that so far?
yes
Good. Now, are you able to simplify \(\sqrt{99}\) ?
3√ 11
right?
Excellent. And do you know what \(\sqrt{-1}\) is?
1
No. The square root of -1 is the imaginary number i. It is referred to in the question. Have you seen it before?
oh yes!
OK. So now your question looks like\[x=-7 + \sqrt{99}\sqrt{-1}\]\[x=-7+3\sqrt{11}i\]Compare this with\[x=a+bi\]What are the values of a and b?
a=-7 b=3√11
Fantastic. Good job!
Thank you sooo much :))))
You're welcome.
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