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hi advance question related to definite integral , i know how to do it but just not sure ?
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i do know answer for i and ii
what were these results you got for (i) and (ii)?
i is just show that
and ii , I got -1
@ganeshie8
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i dunno how to expand it properly
i have done my solution
but not sure
Looks good, In the last line, maybe just leave the answer in exact form : \[\dfrac{\lim\limits_{n\to\infty}~~e^{1/n}(1-e)}{\lim\limits_{n\to\infty}~~n(1-e^{1/n)}}=\dfrac{1(1-e)}{-1}=e-1\]
ok thank u appreciate it @ganeshie8
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np :)
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