Question

help!!
turn in to an inequality
Find the three smallest consecutive even integers whose sum is greater than 126.

Answer 1

does anyone know this?

Answer 2

@jennyrlz

Answer 3

Let (x) = an even integer, (x + 2) = the next even integer and (x+4) be the next even one

So since the sum of these is greater than 126 we have

\[\large x+(x+2)+(x+4) > 126\]

Answer 4

i dont get it?

Answer 5

You dont get what I have written?

Well

Lets say I have an even number...lets call it x

Now to get to the next CONSECUTIVE even number....I need to add 2 to the one I have....if I add 1...it becomes odd

So now I have

x .... and then x+2

And I need the NEXT one as well..so follow suite...add 2 to the previous number we have

x.....then x+2.....and now x+2 + 2 = x + 4

So the 3 consecutive even numbers we have to be summed are

\[\large x + (x+2) + (x+4)\]

Since the question then states, this sum is greater than 126...we just set our number equation accordingly

\[\large x + (x+2) + (x+4) > 126\]

Answer 6

Now we just combine like terms....and evaluate for 'x'

Answer 7

oooh now i get it thnx