what is 2 4/3 equal to? the answer must be in square root form
hmmm sounds what do they mean by "square root form"? that could mean anything
like the answer is an exponent and then there's a radical and then it has a base in the radical
\[2^\frac{ 4 }{3 }\]?
|dw:1442875830908:dw|
yes
actually, got the colors backwards there =) \(\Large { a^{\frac{{\color{blue} n}}{{\color{red} m}}} \implies \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad \sqrt[{\color{red} m}]{a^{\color{blue} n}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}}\qquad thus \\ \quad \\ 2^{\frac{{\color{blue}{ 4}}}{{\color{red}{ 3}}}}\implies ? }\)
so ^4 sqrt 2^3 ?
and then what's after that
hmmm the numerator is the exponent the denominator is the root
\(\large { \sqrt[{\color{red} m}]{a^{\color{blue} n}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}}\qquad thus \\ \quad \\ 2^{\frac{{\color{blue}{ 4}}}{{\color{red}{ 3}}}}\implies \sqrt[{\color{red}{ 3}}]{2^{{\color{blue}{ 4}}}}\implies \sqrt[3]{2\cdot 2\cdot 2\cdot 2\cdot 2}\implies \sqrt[3]{2^3\cdot 2^1}\implies 2\sqrt[3]{2} }\)
hmm actuallly, I have an extra 2 there =) \(\large { \sqrt[{\color{red} m}]{a^{\color{blue} n}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}}\qquad thus \\ \quad \\ 2^{\frac{{\color{blue}{ 4}}}{{\color{red}{ 3}}}}\implies \sqrt[{\color{red}{ 3}}]{2^{{\color{blue}{ 4}}}}\implies \sqrt[3]{2\cdot 2\cdot 2\cdot 2}\implies \sqrt[3]{2^3\cdot 2^1}\implies 2\sqrt[3]{2} }\)
oh so it'd be 3 sqrt 16
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