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Chemistry 11 Online
OpenStudy (anonymous):

How many moles of MgS2O3 are in 167 g of the compound?

OpenStudy (anonymous):

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OpenStudy (anonymous):

I got the molar mass of 120.435amu by adding Mg (24.305) + S (32.066)*2 +O (15.999) *3. so will I divide 167g by 120.435?

OpenStudy (anonymous):

You calculated the molar mass right. Yeah you would divided it

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