Question

Let f(x)=x^2-16. Find f^-1(x).
Can someone check my work?

Answer 1

\[f(x)=x^{2}-16 \]
Step1: Replace f(x) with y.
\[y=x ^{2}-16\]
Step 2: Switch my x and y variables.
\[x=y ^{2}-16\]
Step 3: Add 16 to both sides of the equation.
\[x+16=y ^{2}\]
Step 4: Take the square root of both sides of the equation.
\[\sqrt{x+16}=y\]
Step 5: Replace y with f(x).
\[\sqrt{x+16}=f ^{-1}(x)\]

Did I do this right?

Answer 2

Correct indeed :)

Answer 3

Awesome, thank you! @johnweldon1993

Answer 4

No problem great work!