Question

Can someone help me solve for x?

Answer 1

\[2\sqrt{x-5}=2\]

Answer 2

I know my first step is to subtract 2 from both sides of the equation which gives me...
\[\sqrt{x-5}=0\]
Then I subtract 5 from both sides and I'm left with...
\[\sqrt{x}=5\]
Is there another step after that?

Answer 3

Wooooops! :O

Answer 4

If the 2 was being `added` to the root,
then yes, you would `subtract it from both sides to undo the addition.

Answer 5

But in this case, it looks like the 2 is `multiplying` the root, yes?

Answer 6

So how do we undo multiplication? :)

Answer 7

We divide :D

Answer 8

Good, yes :)
Do that.
It should give you something a little different than 0 on the right side.

Answer 9

Okay, so now I got 1 instead of 0. @zepdrix

Answer 10

\[\large\rm \sqrt{x-5}=1\]Cool.

Answer 11

Then I would add 5 and get \[\sqrt{x}=6\] @zepdrix

Answer 12

Wooops!
The subtraction is `inside` of the root.
We can't do that operation yet.
We need to deal with the root first.

Answer 13

What's the inverse of `square root`?
How do we undo that? :o

Answer 14

Okay so square both sides of the equation? It would still be 1 correct?

Answer 15

\[\large\rm \left(\sqrt{x-5}\right)^2=1^2\]On the left, the operations undo one another, good.
On the right, 1^2 = 1? Sounds good!\[\large\rm x-5=1\]

Answer 16

Okay, then I would add 5 to both sides of the equation correct? @zepdrix

Answer 17

yes

Answer 18

Thank you :) @satellite73

Answer 19

yay good job \c:/