f(x)=(x^2)+1+(1/(x^4)), c=1; (a) find the slope of the line that is tangent to the graph of f(x) at the given point x=c; (b) write an equation of the tangent line to the graph of f(x) at the point (c,f(c))
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
\[f(x)=x^2+1+\frac{1}{x^4}\]?
OpenStudy (clara1223):
yep!
OpenStudy (misty1212):
do you know the derivative?
OpenStudy (misty1212):
lol another county heard from
you got \(f'(x)\)
if not let me know
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OpenStudy (clara1223):
I get that the derivative is 2x-(4/(x^5))
OpenStudy (clara1223):
yeah this is calc
OpenStudy (misty1212):
ok looks good
plug in 1 what do you get?
OpenStudy (clara1223):
-2
OpenStudy (misty1212):
ok so \(m=-2\)
next i guess find \(f(1)\)
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OpenStudy (misty1212):
oh, the answer to question 1 was \(-2\)
now we can find the equation of the tangent line, once we have the point
OpenStudy (clara1223):
how do you construct the equation of the tangent line? I know in class we use y-y1=m(x-x1) and that m=f'(c) but what are y1 and x1?
OpenStudy (anonymous):
\[x_1=1,y_1=f(1)\]
OpenStudy (clara1223):
Oh! duh! (c,f(c)). the question told me that. thanks!!