Does the data in the table represent a direct variation or an inverse variation? Write an equation to model the data in the table.
x
2
4
8
12
y
4
2
mc019-1.jpg
2/3
direct variation; y = 8/x
direct variation; y = 8x
inverse variation; xy = 8
inverse variation; y/x = 8
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OpenStudy (anonymous):
@LynFran
OpenStudy (anonymous):
@AngusV
OpenStudy (anonymous):
@LynFran
OpenStudy (lynfran):
whats mc019.jpg
OpenStudy (anonymous):
2/3
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OpenStudy (anonymous):
I'm stumped on this also
OpenStudy (lynfran):
y=kx is direct variation
y=k/x is an inverse variation
OpenStudy (lynfran):
so lets see
OpenStudy (lynfran):
when x=2 y=4
when x=4 y=2
when x=8 y=??
when x=12 y=2/3
OpenStudy (lynfran):
whats y when x=8
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OpenStudy (lynfran):
im not seeing the value
OpenStudy (lynfran):
this is what im seeing
y
4
2
mc019-1.jpg =====whats this value???
2/3
OpenStudy (anonymous):
it is 1
OpenStudy (lynfran):
ok
OpenStudy (lynfran):
y=kx if its direct variation
we will use when x=2 y=4
so 4=k2
4/2=k
2=k
we will use when x=4 y=2
so 2=k4
2/4=k
1/2=k
when x=8 y=1
1=k8
1/8=k
as we see k is constantly changing
so...this is not direct variation
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OpenStudy (anonymous):
so what is it?
OpenStudy (lynfran):
y=k/x inverse variation
when x=2 y=4
4=k/2
4*2=k
8=k
when x=4 y=2
2=k/4
2*4=k
8=k
when x=8 y=1
1=k/8
1*8=k
8=k
so yes its inverse variation k=8