Question

The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the first number. Find the integers.

Note:only show the problem and the way you work it out.

Answer 1

we need a variable for the first number
you pick

Answer 2

ok

Answer 3

what do you pick?

Answer 4

x

Answer 5

lol no imagination, i would have picked \(\spadesuit\) but \(x\) will do

Answer 6

if the first number is \(x\) and the second number is three times that, how you would write three times \(x\)?

Answer 7

i am doing this on a website called mineracademy. owschool.com and it wont let me use that type of stuff only regular keyboard stuff so....yea

Answer 8

how would you write three times x?

Answer 9

3*x

Answer 10

ok

Answer 11

then how would you write (this is the only hard part) ten less that two times x ?

Answer 12

10-(2*x)

Answer 13

yeah i thought this was the hard part, so lets go slow

Answer 14

if x was 40 then ten less than two times x would be ten less than 80 i.e 70

Answer 15

first multiply by 2, THEN subtract 10

Answer 16

dude i am in 9th grade that part wasn't so hard my top classes are economics and english in 8th grade in reading on my Iowa test i got the adverage of a 12th grader.

Answer 17

economics i never even heard of in 9th grade
in any case "ten less than two times x" would translate as
\[2x-10\]

Answer 18

now add them up and set the result equal to \(92\) i.e solve \[x+3x+2x-10=92\]