Question

Find the difference and simplify:
2/(x^2+3x) - 3/(x^2-9)

Answer 1

\[\huge\rm \frac{ 2 }{ x^2+3x }-\frac{ 3 }{ x^2-9 }\]
factor the denominator

Answer 2

X(x+3)(x-3) ??

Answer 3

for x^2-9
apply the difference of squares \[\huge\rm a^2-b^2=(a+b)(a-b)\]
do you mean x(x+3)(x-3) is a common denominator ?

Answer 4

Yes

Answer 5

I think he went straight to the common denominator (:

Answer 6

true >.<

Answer 7

Would the answer be -1/ x(x+3)(x-3) ??

Answer 8

alright then when we find common denominator
we should multiply the numerator of 1st fraction with the denominator of the 2nd fraction
and multiply the numerator of 2nd fraction with the denominator of first fraction (just like cross multiplication )
here is an example