Question

involving sets E and F. Suppose for this problem that Pr[E]=1/2, Pr[F]=5/16, and Pr[E∩F′]=1/4.
(1) What is Pr[E|F]?


(2) What is Pr[F|E]?

Answer 1

must be some typo here
does it really say \[P(E)=12\]??

Answer 2

sorry i forgot to fix the fractions

Answer 3

or is that maybe
\[P(E)=\frac{1}{2}\]?

Answer 4

its 1/2

Answer 5

how about the rest?

Answer 6

oh nvm i see they are fixed

Answer 7

:)

Answer 8

in any case \[P(A|B)=\frac{P(A\cap B)}{P(B)}\]

Answer 9

so \[P(E|F)=\frac{P(E\cap F)}{P(F)}\] how have those numbers

Answer 10

l meant "you" have those numbers

Answer 11

we don't have P(E∩F)

Answer 12

looks like you wrote it was \(\frac{1}{4}\)

Answer 13

that is Pr[E∩F′]=1/4.

Answer 14

not the same thing as P(E∩F)

Answer 15

you can find \[P(E\cap F)\] by subtracting \[P(E\cap F')\] from \(P(E)\)

Answer 16

really?

Answer 17

can you see it in the picture?

Answer 18

so you are saying its 1/4