Question

Determine whether this function is even or odd

Answer 1

\[h(x)=\frac{ -x^3 }{ 3x^2-9 }\]

Answer 2

Use these two rules-
if h(x) = h(-x) the function is considered even.
if -h(x) = h(-x) the function is considered odd.

Answer 3

I plugged in -x and got neither. Is that right?

Answer 4

so what exactly did you get when you plugged in -x?

Answer 5

\[h(x)=\frac{ x^3 }{ 3x^2-9 }\]

Answer 6

okay and now try and find the function -h(x)

Answer 7

\[h(x)=\frac{ -x^3 }{ -3x^2+9 }\]

Answer 8

No, when you multiply by a negative, you don't have to multiply both the numerator and denominator by the negative. So in this case, you should get \[-\frac{ -x^3 }{ 3x^2 -9}\] and the two negatives should cancel so you get left with \[\frac{ x^3 }{ 3x^2-9 }\]

Answer 9

now that you have found h(x) and -h(x) what do you notice

Answer 10

oooooh silly mistake, so it is ODD!

Answer 11

yup :D

Answer 12

THanks for the help

Answer 13

no problem

Answer 14

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