Ask
your own question, for FREE!
Chemistry
5 Online
A chemical reaction of the general type A->2B is first-order. with a rate constant of 1.52x10-4s-1. A. Calculate the half-life of A. B.Assuming the initial concentration of A is 0.067mol L-1, calculate the time needed for the concentration to fall to 0.010mol L-1.
Still Need Help?
Join the QuestionCove community and study together with friends!
A. the half life for a first order reaction is independent of the initial concentration of A and respond at the formula t1/2= 0.693/k k= rate constant B. use the integrated equation for the first order reaction ln [A]f = -k t + ln [A]o isolate t = time has to be ~ 2.5 half-lifes
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Twaylor:
Time flies doesn't it? I tried to not be the second squeaky wheel of the household and ended up hurting myself and others severely.
clllaaaaaire:
any tips? the quality isn't the best because I am using this site on my computer
Midnight97:
Kinda a roleplay story between me and my friend enjoy... Part one Forgive me for all the screenshots.
StevenisGhost:
what type of song should I make next, and will y'all go check out my new song on
Midnight97:
My drawing sure changed over the years look at these two pictures from 2024 to no
EdwinJsHispanic:
"poem" love is So Beautiful to have. But it's so hard to have. At this point I don't know whether its worth the wait Or if it's just millions of miles to re
EdwinJsHispanic:
"poem" love is So Beautiful to have. But it's so hard to have. At this point I don't know whether its worth the wait Or if it's just millions of miles to re
1 day ago
12 Replies
2 Medals
2 weeks ago
2 Replies
0 Medals
2 weeks ago
2 Replies
1 Medal
1 week ago
6 Replies
2 Medals
2 weeks ago
6 Replies
1 Medal
3 weeks ago
3 Replies
0 Medals
3 weeks ago
0 Replies
0 Medals