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What is the chemical formula for the compound formed between chromium(III) and the iodate ion?
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Chromium(III) has 3 positive charges (which is indicated by the roman numerals in parentheses). The iodate ion, being in group 7, tends to gain an electron (to complete it's octet) and becomes a negative ion with a charge of -1. The formula needs to be an electrically neutral/balanced compound, so we need as many negative charges as positive charges. 1 \(Cr^{3+}\) has 3+ 1 \(I^-\) has 1- we need 3 \(I^-\) to make 3- and balance the 3+ from \(Cr^{3+}\). the formula is \(\sf CrI_3\)
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