Quick question
quick would be having it in the topic \(\uparrow\)
\[\frac{1}{x} = \frac{x - 1}8 - \frac{x}{4} \] My first step would be \[\frac{x-1}{8} - \frac{x \times 2}{4 \times 2}\]
Didn't want to put more than one line of LaTeX in the subject and make it freeze up on me.
I would multiply everything by \(8x\)
\[\huge \frac{ a }{ b } \pm \frac{ c }{ d } \implies \frac{ ad \pm bc }{ bd }\] pretty much with all fractions
I like your style zz
:)
\[\frac{4(x - 1) - 8x}{32} \]
That works
You can now cross multiply with the left side if you like
\[4x - 4 - 8x/32 = 1/x\]
I get it. So when adding or subtracting, we can use the ab + bd/ad rule, and when multiplying, we can cross multiply, and when dividing we can take the recipricol?
Yeah sort of, but know what kind of algebraic rules are going on, when we cross multiply for example we're just multiplying both sides by 32 and x, so yes reciprocal. :)
I mean this rule isn't anything special, it's just as you would do fractions regularly, finding common denominator..etc
In general it is a good idea to learn the following trick \[\dfrac{1}{a}+\dfrac{1}{b}=\dfrac{1}{c}\\ abc\dfrac{1}{a}+abc\dfrac{1}{b}=abc\dfrac{1}{c}\\ bc+ac=ab\] When we have fractions, it is easy to clear the denominators when we have an equals sign!
Hehe yeah, I love that
Especially with partial fractions
Yes. Clearing fractions. I understand. I'm just brushing up on my skills.
word
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