Question

Physics...

Answer 1

@imqwerty

Answer 2

OK, so I have a really specific question. Whenever we study circular motion and aspects of circular motion, I see some solutions including the extra rotational kinetic energy when applying the work-energy theorem and some don't do that.

When is it OK to not include the rotational kinetic energy?

Answer 3

I'll do a followup question as an example to explain why I'm confused here.

Answer 4

If I remember correctly, work-energy theorem is like universal... it works for all kinds of forces; It doesn't matther if the forces are conservative or not.

Conservation of energy requires the forces to be conservative, though.

Answer 5

Could you provide examples to contrast where rotational kinetic energy is included/excluded in work energy equation

Answer 6

This isn't the real question yet, but here's where the confusion arises.\[mgL = \frac{1}{2}mv^2\tag{1} \]\[mgL = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = \frac{1}{2}mL^2 \frac{v^2}{L^2} = mv^2\tag{2}\]I think \(\tag 1\) is wrong and \(\tag 2\) is right.