A photon has a wavelength of 6.2 meters. Calculate the energy of the photon in joules. (Planck's constant is 6.626 × 10È³Ê joule seconds, the speed of light is 2.998 × 10§ m/s)
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OpenStudy (ilovebmth1234):
A. \[3.564*10^{-43}\]
B. \[3.204*10^{-26}\]
C.\[41.08*10^{-34}\]
D. \[13.702*10^{-42}\]
OpenStudy (alexanderphantomhive):
E = hc / λ
E = ((6.626*10^-34)*(2.998*10^8)) / 6.2
E = 3.17*10^-26 J
OpenStudy (alexanderphantomhive):
gosh i really dont know im stumped.
OpenStudy (ilovebmth1234):
that's okay i couldn't figure it out either this equation thing confused me
OpenStudy (ilovebmth1234):
im gonna try your answer and if i get it wrong ill let you know:3
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OpenStudy (abhisar):
Energy = \(\Large\sf \frac{HC}{\lambda}\)
OpenStudy (ilovebmth1234):
wait scratch that most of your answer was right
OpenStudy (abhisar):
What?
OpenStudy (abhisar):
Plug in the values,
Energy = \(\sf \Large \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{6.2}\)
OpenStudy (ilovebmth1234):
i went for answer B witch was closer to @AlexanderPhantomhive's answer she got and i got it right so the answer is B. 3.204x10^-26
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OpenStudy (abhisar):
Yes, that's \(\huge \checkmark\)
OpenStudy (ilovebmth1234):
thank you! both of you for your help :3 i wish i could give both of you medals