A photon has a wavelength of 6.2 meters. Calculate the energy of the photon in joules. (Planck's constant is 6.626 × 10È³Ê joule seconds, the speed of light is 2.998 × 10§ m/s)
A. \[3.564*10^{-43}\] B. \[3.204*10^{-26}\] C.\[41.08*10^{-34}\] D. \[13.702*10^{-42}\]
E = hc / λ E = ((6.626*10^-34)*(2.998*10^8)) / 6.2 E = 3.17*10^-26 J
gosh i really dont know im stumped.
that's okay i couldn't figure it out either this equation thing confused me
im gonna try your answer and if i get it wrong ill let you know:3
Energy = \(\Large\sf \frac{HC}{\lambda}\)
wait scratch that most of your answer was right
What?
Plug in the values, Energy = \(\sf \Large \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{6.2}\)
i went for answer B witch was closer to @AlexanderPhantomhive's answer she got and i got it right so the answer is B. 3.204x10^-26
Yes, that's \(\huge \checkmark\)
thank you! both of you for your help :3 i wish i could give both of you medals
You're most welcome c;
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