Question

The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i.
The length of the hypotenuse is (a-4 or b-5) units, and the area of the triangle is (a-6, b-12) square units

Answer 1

@peachpi @paki

Answer 2

are you supposed to find a and b?

Answer 3

i suppose the length of the hypotenuse can only be 4 or 5 and the are of the triangle can only be 6 or 12

Answer 4

If you draw the points you get this

Answer 5

im still soooo confused algebra is my worst subject!

Answer 6

Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5.

Or you could use the pythagorean theorem
a² + b² = c²
3² + 4² = c²
25 = c²
c = 5

Answer 7

so my answers would be 5 and?

Answer 8

Find the area of the triangle.
A = ½bh = ½(3)(4)

Answer 9

i dont know how to do that...

Answer 10

what's 3*4?

Answer 11

then divide that by 2

Answer 12

so 6?

Answer 13

yes

Answer 14

yay! thank you