Question

Calculus help please
see attached

Answer 1

the problem is y= 4th rooth (x^3-9x-1) *x^5

Answer 2

Simplify the numerator and add two fractions.
\[5 x^4\sqrt[4]{x^3-9x-1}=\frac{5 x^4 \left(x^3-9x-1\right) ^ \frac{1}{4} \, \left(4(x^3-9x-1)^{\frac{ 3 }{ 4 }}\right) }{ 4(x^3-9x-1)^{\frac{ 3 }{ 4 }} }\]

Answer 3

I don't see how you came to multiply the numerator by [4(x^3-9x-1)^(3/4)
or how all simplifying that adds up to 23x^7-189x^5-20x^4

perhaps you could brake the steps down for me, thanks