Use the Distance Formula and the x-axis of the coordinate plane. Show why the distance between two points on a number line (the x-axis) is | a – b |, where a and b are the x-coordinates of the points.
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Do you know the "distance formula" ? Is it in your notes?
d=the square root of x2-x1^2 + y2-y1^2
Are you there? Lol
OS is back. yes that is the correct formula. they want you to use it for two points that lie on the x-axis (that means they y value is 0)
for example, the two points can be (a,0) and (b,0) (if we plot them (if we knew what number a and b were) , they would be on the x-axis any way, use the distance formula to find the distance between those two points. can you try to do that ?
I could use the distance formula to find coordinates but this is just explaining without actual coordinates. It's confusing lol
just use letters instead of numbers.
for example x2 is "b" and x1 is "a" use those letters in the formula the y's are easy: both are 0
So D=(A^2-0^2) + (B^2-0^2) ?
I think you mixed x and y together the formula says \[ D = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\]
Oh so D=(A^2-B^2) + (0^2-0^2)
almost. you don't square each x or y you square the difference. Look at the formula carefully
I see now! Lol It's D=(A-B) + (0-0)
the square root of that
it is \[ D= \sqrt{ (A-B)^2 +(0-0)^2 } \] we can ignore adding zero, so that simplifies to \[ D= \sqrt{ (A-B)^2}\]
now we use the definition \[ |A-B|= \sqrt{(A-B)^2 }\] so show the distance is \[ D= | A-B| \]
Ok is that all?
yes
Thank you!!
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